2x^2-28x=-70

Solution for 2x^2-28x=-70 equation:

2x^2-28x=-70

We move all terms to the left:

2x^2-28x-(-70)=0

We add all the numbers together, and all the variables

2x^2-28x+70=0

a = 2; b = -28; c = +70;
Δ = b2-4ac
Δ = -282-4·2·70
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{14}}{2*2}=\frac{28-4\sqrt{14}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{14}}{2*2}=\frac{28+4\sqrt{14}}{4}
$